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12116016553 is a prime number
BaseRepresentation
bin10110100100010101…
…11011110110101001
31011021101102102010211
423102022323312221
5144303200012203
65322132141121
7606150304264
oct132212736651
934241372124
1012116016553
1151581a2623
1224217677a1
1311b11c5584
1482d1bbcdb
154ada3ac6d
hex2d22bbda9

12116016553 has 2 divisors, whose sum is σ = 12116016554. Its totient is φ = 12116016552.

The previous prime is 12116016547. The next prime is 12116016557. The reversal of 12116016553 is 35561061121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10590879744 + 1525136809 = 102912^2 + 39053^2 .

It is an emirp because it is prime and its reverse (35561061121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12116016553 - 233 = 3526081961 is a prime.

It is a super-2 number, since 2×121160165532 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12116016557) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6058008276 + 6058008277.

It is an arithmetic number, because the mean of its divisors is an integer number (6058008277).

Almost surely, 212116016553 is an apocalyptic number.

It is an amenable number.

12116016553 is a deficient number, since it is larger than the sum of its proper divisors (1).

12116016553 is an equidigital number, since it uses as much as digits as its factorization.

12116016553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5400, while the sum is 31.

Adding to 12116016553 its reverse (35561061121), we get a palindrome (47677077674).

The spelling of 12116016553 in words is "twelve billion, one hundred sixteen million, sixteen thousand, five hundred fifty-three".