Base | Representation |
---|---|
bin | 111000011100000010… |
… | …1010110001110100011 |
3 | 102120211122012102221201 |
4 | 1300320011112032203 |
5 | 3441204200311042 |
6 | 131402320502031 |
7 | 11520310042156 |
oct | 1607005261643 |
9 | 376748172851 |
10 | 121200010147 |
11 | 47445278547 |
12 | 1b5a577a917 |
13 | b5769b3348 |
14 | 5c1a879c9d |
15 | 32454e41b7 |
hex | 1c381563a3 |
121200010147 has 2 divisors, whose sum is σ = 121200010148. Its totient is φ = 121200010146.
The previous prime is 121200010133. The next prime is 121200010223. The reversal of 121200010147 is 741010002121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121200010147 - 211 = 121200008099 is a prime.
It is not a weakly prime, because it can be changed into another prime (121200010247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60600005073 + 60600005074.
It is an arithmetic number, because the mean of its divisors is an integer number (60600005074).
Almost surely, 2121200010147 is an apocalyptic number.
121200010147 is a deficient number, since it is larger than the sum of its proper divisors (1).
121200010147 is an equidigital number, since it uses as much as digits as its factorization.
121200010147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 121200010147 its reverse (741010002121), we get a palindrome (862210012268).
The spelling of 121200010147 in words is "one hundred twenty-one billion, two hundred million, ten thousand, one hundred forty-seven".
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