Base | Representation |
---|---|
bin | 1011000001011110100001… |
… | …1010100100011101111011 |
3 | 1120220122211210001101220202 |
4 | 2300113220122210131323 |
5 | 3042033231004134433 |
6 | 41435504013512415 |
7 | 2360432643243524 |
oct | 260275032443573 |
9 | 46818753041822 |
10 | 12120002021243 |
11 | 395307819a576 |
12 | 1438b301a270b |
13 | 69bbb0133c4c |
14 | 2dc87b2cd84b |
15 | 160408174ee8 |
hex | b05e86a477b |
12120002021243 has 2 divisors, whose sum is σ = 12120002021244. Its totient is φ = 12120002021242.
The previous prime is 12120002021213. The next prime is 12120002021251. The reversal of 12120002021243 is 34212020002121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12120002021243 - 224 = 12119985244027 is a prime.
It is not a weakly prime, because it can be changed into another prime (12120002021213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060001010621 + 6060001010622.
It is an arithmetic number, because the mean of its divisors is an integer number (6060001010622).
Almost surely, 212120002021243 is an apocalyptic number.
12120002021243 is a deficient number, since it is larger than the sum of its proper divisors (1).
12120002021243 is an equidigital number, since it uses as much as digits as its factorization.
12120002021243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 12120002021243 its reverse (34212020002121), we get a palindrome (46332022023364).
The spelling of 12120002021243 in words is "twelve trillion, one hundred twenty billion, two million, twenty-one thousand, two hundred forty-three".
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