Base | Representation |
---|---|
bin | 10001101000110000110… |
… | …101110111010011101101 |
3 | 11021212101101012122011221 |
4 | 101220300311313103231 |
5 | 124324134023012023 |
6 | 2324441334343341 |
7 | 153364331516404 |
oct | 21506065672355 |
9 | 4255341178157 |
10 | 1212000204013 |
11 | 428008577a75 |
12 | 176a884bab51 |
13 | 8a3a27c1341 |
14 | 4293819a63b |
15 | 217d849b85d |
hex | 11a30d774ed |
1212000204013 has 2 divisors, whose sum is σ = 1212000204014. Its totient is φ = 1212000204012.
The previous prime is 1212000203987. The next prime is 1212000204049. The reversal of 1212000204013 is 3104020002121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 846801167524 + 365199036489 = 920218^2 + 604317^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1212000204013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212000204083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606000102006 + 606000102007.
It is an arithmetic number, because the mean of its divisors is an integer number (606000102007).
Almost surely, 21212000204013 is an apocalyptic number.
It is an amenable number.
1212000204013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212000204013 is an equidigital number, since it uses as much as digits as its factorization.
1212000204013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 16.
Adding to 1212000204013 its reverse (3104020002121), we get a palindrome (4316020206134).
The spelling of 1212000204013 in words is "one trillion, two hundred twelve billion, two hundred four thousand, thirteen".
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