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12120044003 = 43019281737
BaseRepresentation
bin10110100100110100…
…10011000111100011
31011021200000000202122
423102122103013203
5144310212402003
65322354334455
7606226450154
oct132232230743
934250000678
1012120044003
11515a4a34a1
122422b8a42b
1311b1ca5792
1482d94992b
154ae084238
hex2d26931e3

12120044003 has 4 divisors (see below), whose sum is σ = 12120368760. Its totient is φ = 12119719248.

The previous prime is 12120043967. The next prime is 12120044021. The reversal of 12120044003 is 30044002121.

12120044003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12120044003 - 26 = 12120043939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12120044023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97850 + ... + 183887.

It is an arithmetic number, because the mean of its divisors is an integer number (3030092190).

Almost surely, 212120044003 is an apocalyptic number.

12120044003 is a deficient number, since it is larger than the sum of its proper divisors (324757).

12120044003 is an equidigital number, since it uses as much as digits as its factorization.

12120044003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 324756.

The product of its (nonzero) digits is 192, while the sum is 17.

Adding to 12120044003 its reverse (30044002121), we get a palindrome (42164046124).

The spelling of 12120044003 in words is "twelve billion, one hundred twenty million, forty-four thousand, three".

Divisors: 1 43019 281737 12120044003