Base | Representation |
---|---|
bin | 11011100011101100110000… |
… | …000101111101100011010111 |
3 | 120220010122122110121122222222 |
4 | 123203230300011331203113 |
5 | 111341222100140320111 |
6 | 1105434422550212555 |
7 | 34346306050240535 |
oct | 3343546005754327 |
9 | 526118573548888 |
10 | 121200488995031 |
11 | 35688925390526 |
12 | 1171557265415b |
13 | 5282207115644 |
14 | 21d01c64c7155 |
15 | e02a822337db |
hex | 6e3b3017d8d7 |
121200488995031 has 2 divisors, whose sum is σ = 121200488995032. Its totient is φ = 121200488995030.
The previous prime is 121200488995021. The next prime is 121200488995111. The reversal of 121200488995031 is 130599884002121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121200488995031 - 210 = 121200488994007 is a prime.
It is a super-2 number, since 2×1212004889950312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (121200488995021) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60600244497515 + 60600244497516.
It is an arithmetic number, because the mean of its divisors is an integer number (60600244497516).
Almost surely, 2121200488995031 is an apocalyptic number.
121200488995031 is a deficient number, since it is larger than the sum of its proper divisors (1).
121200488995031 is an equidigital number, since it uses as much as digits as its factorization.
121200488995031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1244160, while the sum is 53.
The spelling of 121200488995031 in words is "one hundred twenty-one trillion, two hundred billion, four hundred eighty-eight million, nine hundred ninety-five thousand, thirty-one".
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