Base | Representation |
---|---|
bin | 1011000001011110111100… |
… | …0101110100111101011111 |
3 | 1120220200010120210202012122 |
4 | 2300113233011310331133 |
5 | 3042033443142234122 |
6 | 41435523054253155 |
7 | 2360435503250153 |
oct | 260275705647537 |
9 | 46820116722178 |
10 | 12120114024287 |
11 | 395312543a075 |
12 | 1438b617b71bb |
13 | 69bbca3bac39 |
14 | 2dc88c127063 |
15 | 160412deb142 |
hex | b05ef174f5f |
12120114024287 has 2 divisors, whose sum is σ = 12120114024288. Its totient is φ = 12120114024286.
The previous prime is 12120114024259. The next prime is 12120114024407. The reversal of 12120114024287 is 78242041102121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12120114024287 - 210 = 12120114023263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12120114026287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060057012143 + 6060057012144.
It is an arithmetic number, because the mean of its divisors is an integer number (6060057012144).
Almost surely, 212120114024287 is an apocalyptic number.
12120114024287 is a deficient number, since it is larger than the sum of its proper divisors (1).
12120114024287 is an equidigital number, since it uses as much as digits as its factorization.
12120114024287 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14336, while the sum is 35.
The spelling of 12120114024287 in words is "twelve trillion, one hundred twenty billion, one hundred fourteen million, twenty-four thousand, two hundred eighty-seven".
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