12120131201273 has 2 divisors, whose sum is σ = 12120131201274. Its totient is φ = 12120131201272.

The previous prime is 12120131201257. The next prime is 12120131201327. The reversal of 12120131201273 is 37210213102121.

12120131201273 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (12120131201327) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8251388385529 + 3868742815744 = 2872523^2 + 1966912^2 .

It is an emirp because it is prime and its reverse (37210213102121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12120131201273 - 2⁴ = 12120131201257 is a prime.

It is not a weakly prime, because it can be changed into another prime (12120131201203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060065600636 + 6060065600637.

It is an arithmetic number, because the mean of its divisors is an integer number (6060065600637).

Almost surely, 2^{12120131201273} is an apocalyptic number.

It is an amenable number.

12120131201273 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120131201273 is an equidigital number, since it uses as much as digits as its factorization.

12120131201273 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 12120131201273 its reverse (37210213102121), we get a palindrome (49330344303394).

The spelling of 12120131201273 in words is "twelve trillion, one hundred twenty billion, one hundred thirty-one million, two hundred one thousand, two hundred seventy-three".