12120131201327 has 2 divisors, whose sum is σ = 12120131201328. Its totient is φ = 12120131201326.

The previous prime is 12120131201273. The next prime is 12120131201341. The reversal of 12120131201327 is 72310213102121.

12120131201327 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (12120131201273) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12120131201327 - 2¹² = 12120131197231 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12120131201296 and 12120131201305.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12120131201377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060065600663 + 6060065600664.

It is an arithmetic number, because the mean of its divisors is an integer number (6060065600664).

Almost surely, 2^{12120131201327} is an apocalyptic number.

12120131201327 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120131201327 is an equidigital number, since it uses as much as digits as its factorization.

12120131201327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 12120131201327 its reverse (72310213102121), we get a palindrome (84430344303448).

The spelling of 12120131201327 in words is "twelve trillion, one hundred twenty billion, one hundred thirty-one million, two hundred one thousand, three hundred twenty-seven".