Base | Representation |
---|---|
bin | 11011100011101110000001… |
… | …001011111111000011100110 |
3 | 120220010210011021200221010022 |
4 | 123203232001023333003212 |
5 | 111341232341434403200 |
6 | 1105435205551155142 |
7 | 34346354550466550 |
oct | 3343560113770346 |
9 | 526123137627108 |
10 | 121201849528550 |
11 | 3568946337349a |
12 | 11715892215ab2 |
13 | 5282392c5636b |
14 | 21d02b50844d0 |
15 | e02b118ce885 |
hex | 6e3b812ff0e6 |
121201849528550 has 96 divisors (see below), whose sum is σ = 258204815334144. Its totient is φ = 41463927792000.
The previous prime is 121201849528537. The next prime is 121201849528559. The reversal of 121201849528550 is 55825948102121.
It is a junction number, because it is equal to n+sod(n) for n = 121201849528492 and 121201849528501.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121201849528559) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1197915764 + ... + 1198016936.
It is an arithmetic number, because the mean of its divisors is an integer number (2689633493064).
Almost surely, 2121201849528550 is an apocalyptic number.
121201849528550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
121201849528550 is an abundant number, since it is smaller than the sum of its proper divisors (137002965805594).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121201849528550 is a wasteful number, since it uses less digits than its factorization.
121201849528550 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 108654 (or 108649 counting only the distinct ones).
The product of its (nonzero) digits is 2304000, while the sum is 53.
The spelling of 121201849528550 in words is "one hundred twenty-one trillion, two hundred one billion, eight hundred forty-nine million, five hundred twenty-eight thousand, five hundred fifty".
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