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12120202220112 = 24327371795473319
BaseRepresentation
bin1011000001011111010001…
…0110010001001001010000
31120220200100201202120010200
42300113310112101021100
53042034133232020422
641435535524455200
72360440624016640
oct260276426211120
946820321676120
1012120202220112
1139531701a8988
121438b8724a500
1369bc1275a90c
142dc899b24520
1516041aa1d2ac
hexb05f4591250

12120202220112 has 480 divisors, whose sum is σ = 40120817817600. Its totient is φ = 3343366720512.

The previous prime is 12120202220051. The next prime is 12120202220117. The reversal of 12120202220112 is 21102220202121.

It is a happy number.

12120202220112 is a `hidden beast` number, since 12 + 120 + 202 + 220 + 112 = 666.

It is a super-3 number, since 3×121202022201123 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12120202220117) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3651761589 + ... + 3651764907.

It is an arithmetic number, because the mean of its divisors is an integer number (83585037120).

Almost surely, 212120202220112 is an apocalyptic number.

12120202220112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12120202220112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20060408908800).

12120202220112 is an abundant number, since it is smaller than the sum of its proper divisors (28000615597488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12120202220112 is a wasteful number, since it uses less digits than its factorization.

12120202220112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4103 (or 4094 counting only the distinct ones).

The product of its (nonzero) digits is 128, while the sum is 18.

Adding to 12120202220112 its reverse (21102220202121), we get a palindrome (33222422422233).

The spelling of 12120202220112 in words is "twelve trillion, one hundred twenty billion, two hundred two million, two hundred twenty thousand, one hundred twelve".