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1212021433141 is a prime number
BaseRepresentation
bin10001101000110010000…
…110110110001100110101
311021212102212011012001221
4101220302012312030311
5124324204441330031
62324443413350341
7153365010125041
oct21506206661465
94255385135057
101212021433141
11428019557802
12176a936383b1
138a3a701505c
144293ad25021
15217da291a11
hex11a321b6335

1212021433141 has 2 divisors, whose sum is σ = 1212021433142. Its totient is φ = 1212021433140.

The previous prime is 1212021433099. The next prime is 1212021433159. The reversal of 1212021433141 is 1413341202121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 961486146916 + 250535286225 = 980554^2 + 500535^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212021433141 - 219 = 1212020908853 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1212021433241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606010716570 + 606010716571.

It is an arithmetic number, because the mean of its divisors is an integer number (606010716571).

Almost surely, 21212021433141 is an apocalyptic number.

It is an amenable number.

1212021433141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212021433141 is an equidigital number, since it uses as much as digits as its factorization.

1212021433141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1212021433141 its reverse (1413341202121), we get a palindrome (2625362635262).

The spelling of 1212021433141 in words is "one trillion, two hundred twelve billion, twenty-one million, four hundred thirty-three thousand, one hundred forty-one".