12120311223133 has 4 divisors (see below), whose sum is σ = 12758222340160. Its totient is φ = 11482400106108.

The previous prime is 12120311223107. The next prime is 12120311223157. The reversal of 12120311223133 is 33132211302121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12120311223133 - 2¹³ = 12120311214941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12120311223098 and 12120311223107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12120311223833) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 318955558485 + ... + 318955558522.

It is an arithmetic number, because the mean of its divisors is an integer number (3189555585040).

Almost surely, 2^{12120311223133} is an apocalyptic number.

It is an amenable number.

12120311223133 is a deficient number, since it is larger than the sum of its proper divisors (637911117027).

12120311223133 is an equidigital number, since it uses as much as digits as its factorization.

12120311223133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 637911117026.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 12120311223133 its reverse (33132211302121), we get a palindrome (45252522525254).

The spelling of 12120311223133 in words is "twelve trillion, one hundred twenty billion, three hundred eleven million, two hundred twenty-three thousand, one hundred thirty-three".