Base | Representation |
---|---|
bin | 10001101000110010111… |
… | …010000011001100010111 |
3 | 11021212110210102010100212 |
4 | 101220302322003030113 |
5 | 124324221410340303 |
6 | 2324445013200035 |
7 | 153365232200630 |
oct | 21506272031427 |
9 | 4255423363325 |
10 | 1212034855703 |
11 | 428026095331 |
12 | 176a9803001b |
13 | 8a3a9a346b9 |
14 | 4293ca1a887 |
15 | 217db543ad8 |
hex | 11a32e83317 |
1212034855703 has 4 divisors (see below), whose sum is σ = 1385182692240. Its totient is φ = 1038887019168.
The previous prime is 1212034855693. The next prime is 1212034855741. The reversal of 1212034855703 is 3075584302121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1212034855703 - 234 = 1194854986519 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1212034855753) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86573918258 + ... + 86573918271.
It is an arithmetic number, because the mean of its divisors is an integer number (346295673060).
Almost surely, 21212034855703 is an apocalyptic number.
1212034855703 is a deficient number, since it is larger than the sum of its proper divisors (173147836537).
1212034855703 is an equidigital number, since it uses as much as digits as its factorization.
1212034855703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 173147836536.
The product of its (nonzero) digits is 201600, while the sum is 41.
The spelling of 1212034855703 in words is "one trillion, two hundred twelve billion, thirty-four million, eight hundred fifty-five thousand, seven hundred three".
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