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12120431317 is a prime number
BaseRepresentation
bin10110100100110111…
…10001101011010101
31011021200201201001121
423102123301223111
5144310312300232
65322410523541
7606232652311
oct132233615325
934250651047
1012120431317
11515a738495
1224231365b1
1311b20acb67
1482da0ab41
154ae10dd97
hex2d26f1ad5

12120431317 has 2 divisors, whose sum is σ = 12120431318. Its totient is φ = 12120431316.

The previous prime is 12120431261. The next prime is 12120431327. The reversal of 12120431317 is 71313402121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6476064676 + 5644366641 = 80474^2 + 75129^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12120431317 is a prime.

It is a super-2 number, since 2×121204313172 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12120431291 and 12120431300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12120431327) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060215658 + 6060215659.

It is an arithmetic number, because the mean of its divisors is an integer number (6060215659).

Almost surely, 212120431317 is an apocalyptic number.

It is an amenable number.

12120431317 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120431317 is an equidigital number, since it uses as much as digits as its factorization.

12120431317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 12120431317 its reverse (71313402121), we get a palindrome (83433833438).

The spelling of 12120431317 in words is "twelve billion, one hundred twenty million, four hundred thirty-one thousand, three hundred seventeen".