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1212044255431 is a prime number
BaseRepresentation
bin10001101000110011011…
…101111010000011000111
311021212111110002200100221
4101220303131322003013
5124324231312133211
62324445550445211
7153365405120242
oct21506335720307
94255443080327
101212044255431
114280304254a9
12176a9b203807
138a3ab975c79
144293dd86259
15217dc29dc71
hex11a3377a0c7

1212044255431 has 2 divisors, whose sum is σ = 1212044255432. Its totient is φ = 1212044255430.

The previous prime is 1212044255417. The next prime is 1212044255501. The reversal of 1212044255431 is 1345524402121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1212044255431 - 25 = 1212044255399 is a prime.

It is a super-2 number, since 2×12120442554312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1212044255131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606022127715 + 606022127716.

It is an arithmetic number, because the mean of its divisors is an integer number (606022127716).

Almost surely, 21212044255431 is an apocalyptic number.

1212044255431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212044255431 is an equidigital number, since it uses as much as digits as its factorization.

1212044255431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 38400, while the sum is 34.

Adding to 1212044255431 its reverse (1345524402121), we get a palindrome (2557568657552).

The spelling of 1212044255431 in words is "one trillion, two hundred twelve billion, forty-four million, two hundred fifty-five thousand, four hundred thirty-one".