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12120957480397 is a prime number
BaseRepresentation
bin1011000001100010000101…
…0111010110110111001101
31120220202022100220202110211
42300120201113112313031
53042042210103333042
641440142504402421
72360465424434653
oct260304127266715
946822270822424
1012120957480397
113953518561137
121439158176411
1369c0030777ac
142dc92c164dd3
15160461ea9017
hexb06215d6dcd

12120957480397 has 2 divisors, whose sum is σ = 12120957480398. Its totient is φ = 12120957480396.

The previous prime is 12120957480391. The next prime is 12120957480407. The reversal of 12120957480397 is 79308475902121.

12120957480397 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11926565552196 + 194391928201 = 3453486^2 + 440899^2 .

It is a cyclic number.

It is not a de Polignac number, because 12120957480397 - 23 = 12120957480389 is a prime.

It is a super-2 number, since 2×121209574803972 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12120957480391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060478740198 + 6060478740199.

It is an arithmetic number, because the mean of its divisors is an integer number (6060478740199).

Almost surely, 212120957480397 is an apocalyptic number.

It is an amenable number.

12120957480397 is a deficient number, since it is larger than the sum of its proper divisors (1).

12120957480397 is an equidigital number, since it uses as much as digits as its factorization.

12120957480397 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7620480, while the sum is 58.

The spelling of 12120957480397 in words is "twelve trillion, one hundred twenty billion, nine hundred fifty-seven million, four hundred eighty thousand, three hundred ninety-seven".