Base | Representation |
---|---|
bin | 1011000001100010001111… |
… | …1001100011111010010011 |
3 | 1120220202102022221001000022 |
4 | 2300120203321203322103 |
5 | 3042042302000014141 |
6 | 41440151024014055 |
7 | 2360466452032145 |
oct | 260304371437223 |
9 | 46822368831008 |
10 | 12121000001171 |
11 | 395353a563676 |
12 | 143916a46132b |
13 | 69c00bb14809 |
14 | 2dc933a72c95 |
15 | 160465aa7b4b |
hex | b0623e63e93 |
12121000001171 has 2 divisors, whose sum is σ = 12121000001172. Its totient is φ = 12121000001170.
The previous prime is 12121000001167. The next prime is 12121000001183. The reversal of 12121000001171 is 17110000012121.
12121000001171 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is an emirp because it is prime and its reverse (17110000012121) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12121000001171 - 22 = 12121000001167 is a prime.
It is not a weakly prime, because it can be changed into another prime (12121090001171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060500000585 + 6060500000586.
It is an arithmetic number, because the mean of its divisors is an integer number (6060500000586).
Almost surely, 212121000001171 is an apocalyptic number.
12121000001171 is a deficient number, since it is larger than the sum of its proper divisors (1).
12121000001171 is an equidigital number, since it uses as much as digits as its factorization.
12121000001171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28, while the sum is 17.
Adding to 12121000001171 its reverse (17110000012121), we get a palindrome (29231000013292).
The spelling of 12121000001171 in words is "twelve trillion, one hundred twenty-one billion, one thousand, one hundred seventy-one".
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