Base | Representation |
---|---|
bin | 1011000001100010101010… |
… | …0001011010100101010111 |
3 | 1120220202201002000001110001 |
4 | 2300120222201122211113 |
5 | 3042043013421041043 |
6 | 41440210033312131 |
7 | 2360502301331404 |
oct | 260305241324527 |
9 | 46822632001401 |
10 | 12121111112023 |
11 | 3953597253921 |
12 | 143919b705647 |
13 | 69c028b48694 |
14 | 2dc9447172ab |
15 | 16047070474d |
hex | b062a85a957 |
12121111112023 has 2 divisors, whose sum is σ = 12121111112024. Its totient is φ = 12121111112022.
The previous prime is 12121111111969. The next prime is 12121111112101. The reversal of 12121111112023 is 32021111112121.
It is a weak prime.
It is an emirp because it is prime and its reverse (32021111112121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12121111112023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12121111112423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6060555556011 + 6060555556012.
It is an arithmetic number, because the mean of its divisors is an integer number (6060555556012).
Almost surely, 212121111112023 is an apocalyptic number.
12121111112023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12121111112023 is an equidigital number, since it uses as much as digits as its factorization.
12121111112023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 12121111112023 its reverse (32021111112121), we get a palindrome (44142222224144).
The spelling of 12121111112023 in words is "twelve trillion, one hundred twenty-one billion, one hundred eleven million, one hundred twelve thousand, twenty-three".
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