Base | Representation |
---|---|
bin | 10001101000110111100… |
… | …000010101110001100111 |
3 | 11021212200011120120101201 |
4 | 101220313200111301213 |
5 | 124324401133032101 |
6 | 2324500410503331 |
7 | 153400160010451 |
oct | 21506740256147 |
9 | 4255604516351 |
10 | 1212112002151 |
11 | 428065697626 |
12 | 176ab9a34b47 |
13 | 8a3bca05c9b |
14 | 42948d7d2d1 |
15 | 217e31d1e01 |
hex | 11a37815c67 |
1212112002151 has 2 divisors, whose sum is σ = 1212112002152. Its totient is φ = 1212112002150.
The previous prime is 1212112002107. The next prime is 1212112002163. The reversal of 1212112002151 is 1512002112121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1212112002151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212112062151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606056001075 + 606056001076.
It is an arithmetic number, because the mean of its divisors is an integer number (606056001076).
Almost surely, 21212112002151 is an apocalyptic number.
1212112002151 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212112002151 is an equidigital number, since it uses as much as digits as its factorization.
1212112002151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80, while the sum is 19.
Adding to 1212112002151 its reverse (1512002112121), we get a palindrome (2724114114272).
The spelling of 1212112002151 in words is "one trillion, two hundred twelve billion, one hundred twelve million, two thousand, one hundred fifty-one".
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