Base | Representation |
---|---|
bin | 111000011100011001… |
… | …1011101111101010001 |
3 | 102120212110221200201002 |
4 | 1300320303131331101 |
5 | 3441220244203213 |
6 | 131403431551345 |
7 | 11520514565624 |
oct | 1607063357521 |
9 | 376773850632 |
10 | 121212100433 |
11 | 47451086116 |
12 | 1b5a982b555 |
13 | b579357468 |
14 | 5c1c305dbb |
15 | 32465d1658 |
hex | 1c38cddf51 |
121212100433 has 2 divisors, whose sum is σ = 121212100434. Its totient is φ = 121212100432.
The previous prime is 121212100423. The next prime is 121212100459. The reversal of 121212100433 is 334001212121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 106829615104 + 14382485329 = 326848^2 + 119927^2 .
It is a cyclic number.
It is not a de Polignac number, because 121212100433 - 24 = 121212100417 is a prime.
It is not a weakly prime, because it can be changed into another prime (121212100423) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60606050216 + 60606050217.
It is an arithmetic number, because the mean of its divisors is an integer number (60606050217).
Almost surely, 2121212100433 is an apocalyptic number.
It is an amenable number.
121212100433 is a deficient number, since it is larger than the sum of its proper divisors (1).
121212100433 is an equidigital number, since it uses as much as digits as its factorization.
121212100433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 121212100433 its reverse (334001212121), we get a palindrome (455213312554).
The spelling of 121212100433 in words is "one hundred twenty-one billion, two hundred twelve million, one hundred thousand, four hundred thirty-three".
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