Search a number
-
+
1212121220041 is a prime number
BaseRepresentation
bin10001101000111000000…
…011100000001111001001
311021212200210220212222001
4101220320003200033021
5124324411013020131
62324501340231001
7153400331241664
oct21507003401711
94255623825861
101212121220041
1142806a913116
12176b00b3b461
138a3c18b2864
144294a29c6db
15217e3e03261
hex11a380e03c9

1212121220041 has 2 divisors, whose sum is σ = 1212121220042. Its totient is φ = 1212121220040.

The previous prime is 1212121219999. The next prime is 1212121220083. The reversal of 1212121220041 is 1400221212121.

It is a balanced prime because it is at equal distance from previous prime (1212121219999) and next prime (1212121220083).

It can be written as a sum of positive squares in only one way, i.e., 1209164144400 + 2957075641 = 1099620^2 + 54379^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212121220041 - 213 = 1212121211849 is a prime.

It is a super-3 number, since 3×12121212200413 (a number of 37 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (1212121220941) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606060610020 + 606060610021.

It is an arithmetic number, because the mean of its divisors is an integer number (606060610021).

Almost surely, 21212121220041 is an apocalyptic number.

It is an amenable number.

1212121220041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212121220041 is an equidigital number, since it uses as much as digits as its factorization.

1212121220041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 1212121220041 its reverse (1400221212121), we get a palindrome (2612342432162).

The spelling of 1212121220041 in words is "one trillion, two hundred twelve billion, one hundred twenty-one million, two hundred twenty thousand, forty-one".