Base | Representation |
---|---|
bin | 10001101000111000101… |
… | …001010011111101100001 |
3 | 11021212201111120102120020 |
4 | 101220320221103331201 |
5 | 124324421032144413 |
6 | 2324502332504053 |
7 | 153400511421411 |
oct | 21507051237541 |
9 | 4255644512506 |
10 | 1212131131233 |
11 | 428075472590 |
12 | 176b0431b029 |
13 | 8a3c3972b79 |
14 | 4294b71c641 |
15 | 217e4c0ec23 |
hex | 11a38a53f61 |
1212131131233 has 16 divisors (see below), whose sum is σ = 1866811582656. Its totient is φ = 691411696640.
The previous prime is 1212131131231. The next prime is 1212131131279. The reversal of 1212131131233 is 3321311312121.
It is a cyclic number.
It is not a de Polignac number, because 1212131131233 - 21 = 1212131131231 is a prime.
It is a super-5 number, since 5×12121311312335 (a number of 62 digits) contains 55555 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1212131131231) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1080330216 + ... + 1080331337.
It is an arithmetic number, because the mean of its divisors is an integer number (116675723916).
Almost surely, 21212131131233 is an apocalyptic number.
It is an amenable number.
1212131131233 is a deficient number, since it is larger than the sum of its proper divisors (654680451423).
1212131131233 is a wasteful number, since it uses less digits than its factorization.
1212131131233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2160661584.
The product of its digits is 648, while the sum is 24.
Adding to 1212131131233 its reverse (3321311312121), we get a palindrome (4533442443354).
The spelling of 1212131131233 in words is "one trillion, two hundred twelve billion, one hundred thirty-one million, one hundred thirty-one thousand, two hundred thirty-three".
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