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1212131424433 is a prime number
BaseRepresentation
bin10001101000111000101…
…010011011100010110001
311021212201112010022202111
4101220320222123202301
5124324421121040213
62324502343045321
7153400514052256
oct21507052334261
94255645108674
101212131424433
114280756528a6
12176b04440841
138a3c3a46467
144294b79742d
15217e4c6ba3d
hex11a38a9b8b1

1212131424433 has 2 divisors, whose sum is σ = 1212131424434. Its totient is φ = 1212131424432.

The previous prime is 1212131424391. The next prime is 1212131424461. The reversal of 1212131424433 is 3344241312121.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 936776208384 + 275355216049 = 967872^2 + 524743^2 .

It is a cyclic number.

It is not a de Polignac number, because 1212131424433 - 213 = 1212131416241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1212131424395 and 1212131424404.

It is not a weakly prime, because it can be changed into another prime (1212131424473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606065712216 + 606065712217.

It is an arithmetic number, because the mean of its divisors is an integer number (606065712217).

Almost surely, 21212131424433 is an apocalyptic number.

It is an amenable number.

1212131424433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212131424433 is an equidigital number, since it uses as much as digits as its factorization.

1212131424433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 13824, while the sum is 31.

Adding to 1212131424433 its reverse (3344241312121), we get a palindrome (4556372736554).

The spelling of 1212131424433 in words is "one trillion, two hundred twelve billion, one hundred thirty-one million, four hundred twenty-four thousand, four hundred thirty-three".