Base | Representation |
---|---|
bin | 1011000001100101111110… |
… | …1000101001010101011111 |
3 | 1120220212000011202000012212 |
4 | 2300121133220221111133 |
5 | 3042101330030344103 |
6 | 41440434304351035 |
7 | 2360533341421301 |
oct | 260313750512537 |
9 | 46825004660185 |
10 | 12122002199903 |
11 | 3953a04249392 |
12 | 14393aa01547b |
13 | 69c13b64170b |
14 | 2dc9cabd3971 |
15 | 1604c3a707d8 |
hex | b065fa2955f |
12122002199903 has 2 divisors, whose sum is σ = 12122002199904. Its totient is φ = 12122002199902.
The previous prime is 12122002199897. The next prime is 12122002200037. The reversal of 12122002199903 is 30999120022121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12122002199903 - 24 = 12122002199887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12122002199303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061001099951 + 6061001099952.
It is an arithmetic number, because the mean of its divisors is an integer number (6061001099952).
Almost surely, 212122002199903 is an apocalyptic number.
12122002199903 is a deficient number, since it is larger than the sum of its proper divisors (1).
12122002199903 is an equidigital number, since it uses as much as digits as its factorization.
12122002199903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 41.
The spelling of 12122002199903 in words is "twelve trillion, one hundred twenty-two billion, two million, one hundred ninety-nine thousand, nine hundred three".
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