Search a number
-
+
121221323437 is a prime number
BaseRepresentation
bin111000011100101011…
…0101001101010101101
3102120220010022021021211
41300321112221222231
53441230124322222
6131404401354421
711520656151064
oct1607126515255
9376803267254
10121221323437
1147456305535
121b5b0938a11
13b57b236466
145c1d6271db
153247304277
hex1c395a9aad

121221323437 has 2 divisors, whose sum is σ = 121221323438. Its totient is φ = 121221323436.

The previous prime is 121221323351. The next prime is 121221323449. The reversal of 121221323437 is 734323122121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 69011815401 + 52209508036 = 262701^2 + 228494^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121221323437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121221323399 and 121221323408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121221323497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60610661718 + 60610661719.

It is an arithmetic number, because the mean of its divisors is an integer number (60610661719).

Almost surely, 2121221323437 is an apocalyptic number.

It is an amenable number.

121221323437 is a deficient number, since it is larger than the sum of its proper divisors (1).

121221323437 is an equidigital number, since it uses as much as digits as its factorization.

121221323437 is an evil number, because the sum of its binary digits is even.

The product of its digits is 12096, while the sum is 31.

Adding to 121221323437 its reverse (734323122121), we get a palindrome (855544445558).

The spelling of 121221323437 in words is "one hundred twenty-one billion, two hundred twenty-one million, three hundred twenty-three thousand, four hundred thirty-seven".