Base | Representation |
---|---|
bin | 11011100100000000111000… |
… | …110100010100000011000011 |
3 | 120220012201110021201200101022 |
4 | 123210000320310110003003 |
5 | 111342100340202400003 |
6 | 1105452400231500055 |
7 | 34351002616402541 |
oct | 3344007064240303 |
9 | 526181407650338 |
10 | 121222110200003 |
11 | 3569700aa5486a |
12 | 117197a752762b |
13 | 528427163ba57 |
14 | 21d1277c22d91 |
15 | e033ea48b738 |
hex | 6e4038d140c3 |
121222110200003 has 6 divisors (see below), whose sum is σ = 125258642486532. Its totient is φ = 117311719547460.
The previous prime is 121222110199987. The next prime is 121222110200029. The reversal of 121222110200003 is 300002011222121.
It is not a de Polignac number, because 121222110200003 - 24 = 121222110199987 is a prime.
It is a super-2 number, since 2×1212221102000032 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121222110200203) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 63070816001 + ... + 63070817922.
It is an arithmetic number, because the mean of its divisors is an integer number (20876440414422).
Almost surely, 2121222110200003 is an apocalyptic number.
121222110200003 is a deficient number, since it is larger than the sum of its proper divisors (4036532286529).
121222110200003 is an equidigital number, since it uses as much as digits as its factorization.
121222110200003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126141633985 (or 126141633954 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 121222110200003 its reverse (300002011222121), we get a palindrome (421224121422124).
The spelling of 121222110200003 in words is "one hundred twenty-one trillion, two hundred twenty-two billion, one hundred ten million, two hundred thousand, three".
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