Base | Representation |
---|---|
bin | 111000011100101100… |
… | …1101110110110111011 |
3 | 102120220011211022020102 |
4 | 1300321121232312323 |
5 | 3441230331144011 |
6 | 131404430550015 |
7 | 11520666053633 |
oct | 1607131566673 |
9 | 376804738212 |
10 | 121222131131 |
11 | 47456807352 |
12 | 1b5b106830b |
13 | b57b459c9a |
14 | 5c1d7976c3 |
15 | 324741373b |
hex | 1c3966edbb |
121222131131 has 2 divisors, whose sum is σ = 121222131132. Its totient is φ = 121222131130.
The previous prime is 121222131109. The next prime is 121222131161. The reversal of 121222131131 is 131131222121.
It is a weak prime.
It is an emirp because it is prime and its reverse (131131222121) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121222131131 is a prime.
It is a super-2 number, since 2×1212221311312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121222131161) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60611065565 + 60611065566.
It is an arithmetic number, because the mean of its divisors is an integer number (60611065566).
Almost surely, 2121222131131 is an apocalyptic number.
121222131131 is a deficient number, since it is larger than the sum of its proper divisors (1).
121222131131 is an equidigital number, since it uses as much as digits as its factorization.
121222131131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 144, while the sum is 20.
Adding to 121222131131 its reverse (131131222121), we get a palindrome (252353353252).
The spelling of 121222131131 in words is "one hundred twenty-one billion, two hundred twenty-two million, one hundred thirty-one thousand, one hundred thirty-one".
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