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121222131131 is a prime number
BaseRepresentation
bin111000011100101100…
…1101110110110111011
3102120220011211022020102
41300321121232312323
53441230331144011
6131404430550015
711520666053633
oct1607131566673
9376804738212
10121222131131
1147456807352
121b5b106830b
13b57b459c9a
145c1d7976c3
15324741373b
hex1c3966edbb

121222131131 has 2 divisors, whose sum is σ = 121222131132. Its totient is φ = 121222131130.

The previous prime is 121222131109. The next prime is 121222131161. The reversal of 121222131131 is 131131222121.

It is a weak prime.

It is an emirp because it is prime and its reverse (131131222121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121222131131 is a prime.

It is a super-2 number, since 2×1212221311312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (121222131161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60611065565 + 60611065566.

It is an arithmetic number, because the mean of its divisors is an integer number (60611065566).

Almost surely, 2121222131131 is an apocalyptic number.

121222131131 is a deficient number, since it is larger than the sum of its proper divisors (1).

121222131131 is an equidigital number, since it uses as much as digits as its factorization.

121222131131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 20.

Adding to 121222131131 its reverse (131131222121), we get a palindrome (252353353252).

The spelling of 121222131131 in words is "one hundred twenty-one billion, two hundred twenty-two million, one hundred thirty-one thousand, one hundred thirty-one".