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12122223300133 = 18166973609393
BaseRepresentation
bin1011000001100110110011…
…0100000100111000100101
31120220212120120210001201021
42300121230310010320211
53042102303131101013
641440512243331141
72360541664636342
oct260315464047045
946825516701637
1012122223300133
113954008033251
121439450080ab1
1369c1753a5b5b
142dca0c3097c9
151604d8196a8d
hexb066cd04e25

12122223300133 has 4 divisors (see below), whose sum is σ = 12189196909708. Its totient is φ = 12055249690560.

The previous prime is 12122223300097. The next prime is 12122223300163. The reversal of 12122223300133 is 33100332222121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4642999276644 + 7479224023489 = 2154762^2 + 2734817^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12122223300133 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12122223300098 and 12122223300107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12122223300163) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33486804516 + ... + 33486804877.

It is an arithmetic number, because the mean of its divisors is an integer number (3047299227427).

Almost surely, 212122223300133 is an apocalyptic number.

It is an amenable number.

12122223300133 is a deficient number, since it is larger than the sum of its proper divisors (66973609575).

12122223300133 is an equidigital number, since it uses as much as digits as its factorization.

12122223300133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66973609574.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 12122223300133 its reverse (33100332222121), we get a palindrome (45222555522254).

The spelling of 12122223300133 in words is "twelve trillion, one hundred twenty-two billion, two hundred twenty-three million, three hundred thousand, one hundred thirty-three".

Divisors: 1 181 66973609393 12122223300133