Base | Representation |
---|---|
bin | 10110100101000111… |
… | …10111011100110001 |
3 | 1011021211201110020121 |
4 | 23102203313130301 |
5 | 144311333131423 |
6 | 5322524210241 |
7 | 606256664350 |
oct | 132243673461 |
9 | 34254643217 |
10 | 12122552113 |
11 | 5160956911 |
12 | 2423999981 |
13 | 11b2673279 |
14 | 82dddd997 |
15 | 4ae3cc45d |
hex | 2d28f7731 |
12122552113 has 4 divisors (see below), whose sum is σ = 13854345280. Its totient is φ = 10390758948.
The previous prime is 12122552111. The next prime is 12122552129. The reversal of 12122552113 is 31125522121.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31125522121 = 61 ⋅510254461.
It is a cyclic number.
It is not a de Polignac number, because 12122552113 - 21 = 12122552111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12122552111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 865896573 + ... + 865896586.
It is an arithmetic number, because the mean of its divisors is an integer number (3463586320).
Almost surely, 212122552113 is an apocalyptic number.
It is an amenable number.
12122552113 is a deficient number, since it is larger than the sum of its proper divisors (1731793167).
12122552113 is an equidigital number, since it uses as much as digits as its factorization.
12122552113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1731793166.
The product of its digits is 1200, while the sum is 25.
The spelling of 12122552113 in words is "twelve billion, one hundred twenty-two million, five hundred fifty-two thousand, one hundred thirteen".
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