Base | Representation |
---|---|
bin | 1011000001101001110100… |
… | …0110000010000000010101 |
3 | 1120220221200000221222212222 |
4 | 2300122131012002000111 |
5 | 3042110433012011201 |
6 | 41441124500552125 |
7 | 2360601031635641 |
oct | 260323506020025 |
9 | 46827600858788 |
10 | 12123033313301 |
11 | 3954393293119 |
12 | 14396373b2645 |
13 | 69c2741535a1 |
14 | 2dca87b1dc21 |
15 | 16053434a91b |
hex | b069d182015 |
12123033313301 has 2 divisors, whose sum is σ = 12123033313302. Its totient is φ = 12123033313300.
The previous prime is 12123033313241. The next prime is 12123033313351. The reversal of 12123033313301 is 10331333032121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8212803908401 + 3910229404900 = 2865799^2 + 1977430^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12123033313301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12123033313351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6061516656650 + 6061516656651.
It is an arithmetic number, because the mean of its divisors is an integer number (6061516656651).
Almost surely, 212123033313301 is an apocalyptic number.
It is an amenable number.
12123033313301 is a deficient number, since it is larger than the sum of its proper divisors (1).
12123033313301 is an equidigital number, since it uses as much as digits as its factorization.
12123033313301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916, while the sum is 26.
Adding to 12123033313301 its reverse (10331333032121), we get a palindrome (22454366345422).
The spelling of 12123033313301 in words is "twelve trillion, one hundred twenty-three billion, thirty-three million, three hundred thirteen thousand, three hundred one".
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