Base | Representation |
---|---|
bin | 10001101001000011100… |
… | …100011100000110100111 |
3 | 11021220012021102121111022 |
4 | 101221003210130012213 |
5 | 124330304441400424 |
6 | 2324532441001355 |
7 | 153405165255212 |
oct | 21510344340647 |
9 | 4256167377438 |
10 | 1212314403239 |
11 | 42815996a555 |
12 | 176b5578325b |
13 | 8a422921144 |
14 | 42967bc8779 |
15 | 21805d6295e |
hex | 11a4391c1a7 |
1212314403239 has 2 divisors, whose sum is σ = 1212314403240. Its totient is φ = 1212314403238.
The previous prime is 1212314403197. The next prime is 1212314403247. The reversal of 1212314403239 is 9323044132121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1212314403239 - 28 = 1212314402983 is a prime.
It is a super-2 number, since 2×12123144032392 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1212314403199 and 1212314403208.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1212314403259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606157201619 + 606157201620.
It is an arithmetic number, because the mean of its divisors is an integer number (606157201620).
Almost surely, 21212314403239 is an apocalyptic number.
1212314403239 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212314403239 is an equidigital number, since it uses as much as digits as its factorization.
1212314403239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 1212314403239 in words is "one trillion, two hundred twelve billion, three hundred fourteen million, four hundred three thousand, two hundred thirty-nine".
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