1212322311133 has 4 divisors (see below), whose sum is σ = 1219759871488. Its totient is φ = 1204884750780.

The previous prime is 1212322311103. The next prime is 1212322311157. The reversal of 1212322311133 is 3311132232121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1212322311133 - 2¹³ = 1212322302941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1212322311098 and 1212322311107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1212322311103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3718779933 + ... + 3718780258.

It is an arithmetic number, because the mean of its divisors is an integer number (304939967872).

Almost surely, 2^{1212322311133} is an apocalyptic number.

It is an amenable number.

1212322311133 is a deficient number, since it is larger than the sum of its proper divisors (7437560355).

1212322311133 is an equidigital number, since it uses as much as digits as its factorization.

1212322311133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7437560354.

The product of its digits is 1296, while the sum is 25.

Adding to 1212322311133 its reverse (3311132232121), we get a palindrome (4523454543254).

The spelling of 1212322311133 in words is "one trillion, two hundred twelve billion, three hundred twenty-two million, three hundred eleven thousand, one hundred thirty-three".