121241204311333 has 4 divisors (see below), whose sum is σ = 121241595431008. Its totient is φ = 121240813191660.

The previous prime is 121241204311319. The next prime is 121241204311373. The reversal of 121241204311333 is 333113402142121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121241204311333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 121241204311295 and 121241204311304.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121241204311313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195094491 + ... + 195714952.

It is an arithmetic number, because the mean of its divisors is an integer number (30310398857752).

Almost surely, 2^{121241204311333} is an apocalyptic number.

It is an amenable number.

121241204311333 is a deficient number, since it is larger than the sum of its proper divisors (391119675).

121241204311333 is an equidigital number, since it uses as much as digits as its factorization.

121241204311333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 391119674.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 121241204311333 its reverse (333113402142121), we get a palindrome (454354606453454).

The spelling of 121241204311333 in words is "one hundred twenty-one trillion, two hundred forty-one billion, two hundred four million, three hundred eleven thousand, three hundred thirty-three".