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12124325003 = 71732046429
BaseRepresentation
bin10110100101010101…
…01000010010001011
31011021222001112012012
423102222220102023
5144312311400003
65323030210135
7606311030210
oct132252502213
934258045165
1012124325003
11516195790a
1224244b394b
1311b2b4420b
14830341b07
154ae62c8d8
hex2d2aa848b

12124325003 has 4 divisors (see below), whose sum is σ = 13856371440. Its totient is φ = 10392278568.

The previous prime is 12124324957. The next prime is 12124325027. The reversal of 12124325003 is 30052342121.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12124325003 - 28 = 12124324747 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12124325003.

It is not an unprimeable number, because it can be changed into a prime (12124325503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 866023208 + ... + 866023221.

It is an arithmetic number, because the mean of its divisors is an integer number (3464092860).

Almost surely, 212124325003 is an apocalyptic number.

12124325003 is a deficient number, since it is larger than the sum of its proper divisors (1732046437).

12124325003 is an equidigital number, since it uses as much as digits as its factorization.

12124325003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1732046436.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 12124325003 its reverse (30052342121), we get a palindrome (42176667124).

The spelling of 12124325003 in words is "twelve billion, one hundred twenty-four million, three hundred twenty-five thousand, three".

Divisors: 1 7 1732046429 12124325003