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12124325113 is a prime number
BaseRepresentation
bin10110100101010101…
…01000010011111001
31011021222001112100021
423102222220103321
5144312311400423
65323030210441
7606311030425
oct132252502371
934258045307
1012124325113
1151619579aa
1224244b3a21
1311b2b44294
14830341b85
154ae62c95d
hex2d2aa84f9

12124325113 has 2 divisors, whose sum is σ = 12124325114. Its totient is φ = 12124325112.

The previous prime is 12124325099. The next prime is 12124325141. The reversal of 12124325113 is 31152342121.

12124325113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9843020944 + 2281304169 = 99212^2 + 47763^2 .

It is a cyclic number.

It is not a de Polignac number, because 12124325113 - 29 = 12124324601 is a prime.

It is not a weakly prime, because it can be changed into another prime (12124325173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6062162556 + 6062162557.

It is an arithmetic number, because the mean of its divisors is an integer number (6062162557).

Almost surely, 212124325113 is an apocalyptic number.

It is an amenable number.

12124325113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12124325113 is an equidigital number, since it uses as much as digits as its factorization.

12124325113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1440, while the sum is 25.

Adding to 12124325113 its reverse (31152342121), we get a palindrome (43276667234).

The spelling of 12124325113 in words is "twelve billion, one hundred twenty-four million, three hundred twenty-five thousand, one hundred thirteen".