Base | Representation |
---|---|
bin | 11011100100010101011001… |
… | …010111000111100100000011 |
3 | 120220021211021221210211000121 |
4 | 123210111121113013210003 |
5 | 111342430440021000144 |
6 | 1105510441310401111 |
7 | 34352412410362063 |
oct | 3344253127074403 |
9 | 526254257724017 |
10 | 121244131031299 |
11 | 356a53901592a1 |
12 | 11721b12200197 |
13 | 52863708a5643 |
14 | 21d23666673a3 |
15 | e03c88832384 |
hex | 6e45595c7903 |
121244131031299 has 2 divisors, whose sum is σ = 121244131031300. Its totient is φ = 121244131031298.
The previous prime is 121244131031209. The next prime is 121244131031329. The reversal of 121244131031299 is 992130131442121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 121244131031299 - 217 = 121244130900227 is a prime.
It is a super-2 number, since 2×1212441310312992 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (121244131031209) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60622065515649 + 60622065515650.
It is an arithmetic number, because the mean of its divisors is an integer number (60622065515650).
Almost surely, 2121244131031299 is an apocalyptic number.
121244131031299 is a deficient number, since it is larger than the sum of its proper divisors (1).
121244131031299 is an equidigital number, since it uses as much as digits as its factorization.
121244131031299 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 93312, while the sum is 43.
The spelling of 121244131031299 in words is "one hundred twenty-one trillion, two hundred forty-four billion, one hundred thirty-one million, thirty-one thousand, two hundred ninety-nine".
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