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12125080752101 is a prime number
BaseRepresentation
bin1011000001110001011100…
…1000011000111111100101
31120221010221201120122220122
42300130113020120333211
53042124131133031401
641442104000411325
72361002542610162
oct260342710307745
946833851518818
1012125080752101
113955243a911a9
121439b09016b45
1369c50c39a335
142dcbdda07069
15160603e7e21b
hexb0717218fe5

12125080752101 has 2 divisors, whose sum is σ = 12125080752102. Its totient is φ = 12125080752100.

The previous prime is 12125080752089. The next prime is 12125080752139. The reversal of 12125080752101 is 10125708052121.

12125080752101 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11783779428001 + 341301324100 = 3432751^2 + 584210^2 .

It is a cyclic number.

It is not a de Polignac number, because 12125080752101 - 214 = 12125080735717 is a prime.

It is a super-3 number, since 3×121250807521013 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12125080752151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6062540376050 + 6062540376051.

It is an arithmetic number, because the mean of its divisors is an integer number (6062540376051).

Almost surely, 212125080752101 is an apocalyptic number.

It is an amenable number.

12125080752101 is a deficient number, since it is larger than the sum of its proper divisors (1).

12125080752101 is an equidigital number, since it uses as much as digits as its factorization.

12125080752101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 11200, while the sum is 35.

The spelling of 12125080752101 in words is "twelve trillion, one hundred twenty-five billion, eighty million, seven hundred fifty-two thousand, one hundred one".