Base | Representation |
---|---|
bin | 10110100101011011… |
… | …11110011100111001 |
3 | 1011022000201002112012 |
4 | 23102231332130321 |
5 | 144313022432413 |
6 | 5323101055305 |
7 | 606321342554 |
oct | 132255763471 |
9 | 34260632465 |
10 | 12125202233 |
11 | 51623a69a1 |
12 | 2424857535 |
13 | 11b30905a1 |
14 | 8304cd69b |
15 | 4ae7527a8 |
hex | 2d2b7e739 |
12125202233 has 2 divisors, whose sum is σ = 12125202234. Its totient is φ = 12125202232.
The previous prime is 12125202211. The next prime is 12125202251. The reversal of 12125202233 is 33220252121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9666232489 + 2458969744 = 98317^2 + 49588^2 .
It is a cyclic number.
It is not a de Polignac number, because 12125202233 - 222 = 12121007929 is a prime.
It is a super-2 number, since 2×121252022332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12125202199 and 12125202208.
It is not a weakly prime, because it can be changed into another prime (12125202263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6062601116 + 6062601117.
It is an arithmetic number, because the mean of its divisors is an integer number (6062601117).
Almost surely, 212125202233 is an apocalyptic number.
It is an amenable number.
12125202233 is a deficient number, since it is larger than the sum of its proper divisors (1).
12125202233 is an equidigital number, since it uses as much as digits as its factorization.
12125202233 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 12125202233 its reverse (33220252121), we get a palindrome (45345454354).
The spelling of 12125202233 in words is "twelve billion, one hundred twenty-five million, two hundred two thousand, two hundred thirty-three".
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