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12126050321149 is a prime number
BaseRepresentation
bin1011000001110101000011…
…1011000000001011111101
31120221020110021222212121101
42300131100323000023331
53042133122340234044
641442344113533101
72361035555036122
oct260352073001375
946836407885541
1012126050321149
1139556a130a836
12143a139874191
1369c63521132b
142dcc926b2749
1516065e14dcd4
hexb0750ec02fd

12126050321149 has 2 divisors, whose sum is σ = 12126050321150. Its totient is φ = 12126050321148.

The previous prime is 12126050321131. The next prime is 12126050321171. The reversal of 12126050321149 is 94112305062121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11985963305625 + 140087015524 = 3462075^2 + 374282^2 .

It is a cyclic number.

It is not a de Polignac number, because 12126050321149 - 217 = 12126050190077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12126050321449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6063025160574 + 6063025160575.

It is an arithmetic number, because the mean of its divisors is an integer number (6063025160575).

Almost surely, 212126050321149 is an apocalyptic number.

It is an amenable number.

12126050321149 is a deficient number, since it is larger than the sum of its proper divisors (1).

12126050321149 is an equidigital number, since it uses as much as digits as its factorization.

12126050321149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 25920, while the sum is 37.

The spelling of 12126050321149 in words is "twelve trillion, one hundred twenty-six billion, fifty million, three hundred twenty-one thousand, one hundred forty-nine".