1213001020037 has 2 divisors, whose sum is σ = 1213001020038. Its totient is φ = 1213001020036.

The previous prime is 1213001019869. The next prime is 1213001020073. The reversal of 1213001020037 is 7300201003121.

Together with next prime (1213001020073) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 996590910436 + 216410109601 = 998294^2 + 465199^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213001020037 - 2²⁶ = 1212933911173 is a prime.

It is a super-2 number, since 2×1213001020037² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1213001020097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606500510018 + 606500510019.

It is an arithmetic number, because the mean of its divisors is an integer number (606500510019).

Almost surely, 2^{1213001020037} is an apocalyptic number.

It is an amenable number.

1213001020037 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213001020037 is an equidigital number, since it uses as much as digits as its factorization.

1213001020037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 20.

Adding to 1213001020037 its reverse (7300201003121), we get a palindrome (8513202023158).

The spelling of 1213001020037 in words is "one trillion, two hundred thirteen billion, one million, twenty thousand, thirty-seven".