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1213001031103 = 2207549615329
BaseRepresentation
bin10001101001101100011…
…111101101110110111111
311021221222010102220211221
4101221230133231312333
5124333211230443403
62325124525454211
7153431203433551
oct21515437556677
94257863386757
101213001031103
114284815061a4
12177107711367
138a501c5ab14
14429d10814d1
1521846292dbd
hex11a6c7eddbf

1213001031103 has 4 divisors (see below), whose sum is σ = 1213550648640. Its totient is φ = 1212451413568.

The previous prime is 1213001031091. The next prime is 1213001031107. The reversal of 1213001031103 is 3011301003121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1213001031103 - 213 = 1213001022911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1213001031107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 274805458 + ... + 274809871.

It is an arithmetic number, because the mean of its divisors is an integer number (303387662160).

Almost surely, 21213001031103 is an apocalyptic number.

1213001031103 is a deficient number, since it is larger than the sum of its proper divisors (549617537).

1213001031103 is an equidigital number, since it uses as much as digits as its factorization.

1213001031103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 549617536.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 1213001031103 its reverse (3011301003121), we get a palindrome (4224302034224).

The spelling of 1213001031103 in words is "one trillion, two hundred thirteen billion, one million, thirty-one thousand, one hundred three".

Divisors: 1 2207 549615329 1213001031103