Base | Representation |
---|---|
bin | 111000011111000001… |
… | …1101101011111000111 |
3 | 102121002121210212112022 |
4 | 1300332003231133013 |
5 | 3441410330310143 |
6 | 131420301113355 |
7 | 11522635031321 |
oct | 1607603553707 |
9 | 377077725468 |
10 | 121300244423 |
11 | 47496909a96 |
12 | 1b61325885b |
13 | b5916a9677 |
14 | 5c29ccc611 |
15 | 324e1e3268 |
hex | 1c3e0ed7c7 |
121300244423 has 4 divisors (see below), whose sum is σ = 122026593360. Its totient is φ = 120573895488.
The previous prime is 121300244413. The next prime is 121300244489. The reversal of 121300244423 is 324442003121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 121300244423 - 24 = 121300244407 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 121300244392 and 121300244401.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121300244413) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 363174218 + ... + 363174551.
It is an arithmetic number, because the mean of its divisors is an integer number (30506648340).
Almost surely, 2121300244423 is an apocalyptic number.
121300244423 is a deficient number, since it is larger than the sum of its proper divisors (726348937).
121300244423 is an equidigital number, since it uses as much as digits as its factorization.
121300244423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 726348936.
The product of its (nonzero) digits is 4608, while the sum is 26.
Adding to 121300244423 its reverse (324442003121), we get a palindrome (445742247544).
The spelling of 121300244423 in words is "one hundred twenty-one billion, three hundred million, two hundred forty-four thousand, four hundred twenty-three".
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