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1213004310211 = 4015130211061
BaseRepresentation
bin10001101001101100101…
…100001110011011000011
311021221222100121111221101
4101221230230032123003
5124333213100411321
62325125124035231
7153431243341621
oct21515454163303
94257870544841
101213004310211
11428483345901
12177108832b17
138a502838515
14429d1696511
15218466de791
hex11a6cb0e6c3

1213004310211 has 4 divisors (see below), whose sum is σ = 1213034561424. Its totient is φ = 1212974059000.

The previous prime is 1213004310191. The next prime is 1213004310233. The reversal of 1213004310211 is 1120134003121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1213004310211 - 211 = 1213004308163 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1213004314211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15065380 + ... + 15145681.

It is an arithmetic number, because the mean of its divisors is an integer number (303258640356).

Almost surely, 21213004310211 is an apocalyptic number.

1213004310211 is a deficient number, since it is larger than the sum of its proper divisors (30251213).

1213004310211 is an equidigital number, since it uses as much as digits as its factorization.

1213004310211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30251212.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 1213004310211 its reverse (1120134003121), we get a palindrome (2333138313332).

The spelling of 1213004310211 in words is "one trillion, two hundred thirteen billion, four million, three hundred ten thousand, two hundred eleven".

Divisors: 1 40151 30211061 1213004310211