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1213004310233 is a prime number
BaseRepresentation
bin10001101001101100101…
…100001110011011011001
311021221222100121111222012
4101221230230032123121
5124333213100411413
62325125124035305
7153431243341652
oct21515454163331
94257870544865
101213004310233
11428483345921
12177108832b35
138a502838531
14429d1696529
15218466de7a8
hex11a6cb0e6d9

1213004310233 has 2 divisors, whose sum is σ = 1213004310234. Its totient is φ = 1213004310232.

The previous prime is 1213004310191. The next prime is 1213004310239. The reversal of 1213004310233 is 3320134003121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 775717039504 + 437287270729 = 880748^2 + 661277^2 .

It is a cyclic number.

It is not a de Polignac number, because 1213004310233 - 238 = 938126403289 is a prime.

It is a super-2 number, since 2×12130043102332 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1213004310199 and 1213004310208.

It is not a weakly prime, because it can be changed into another prime (1213004310239) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606502155116 + 606502155117.

It is an arithmetic number, because the mean of its divisors is an integer number (606502155117).

Almost surely, 21213004310233 is an apocalyptic number.

It is an amenable number.

1213004310233 is a deficient number, since it is larger than the sum of its proper divisors (1).

1213004310233 is an equidigital number, since it uses as much as digits as its factorization.

1213004310233 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1213004310233 its reverse (3320134003121), we get a palindrome (4533138313354).

The spelling of 1213004310233 in words is "one trillion, two hundred thirteen billion, four million, three hundred ten thousand, two hundred thirty-three".