Base | Representation |
---|---|
bin | 1011000010000100000000… |
… | …1000111000000010111111 |
3 | 1120221121210222220021110112 |
4 | 2300201000020320002333 |
5 | 3042214332302244242 |
6 | 41444250242500235 |
7 | 2361240200225312 |
oct | 260410010700277 |
9 | 46847728807415 |
10 | 12130063712447 |
11 | 395737081004a |
12 | 143aa7996467b |
13 | 69cb24841095 |
14 | 2dd153710979 |
15 | 1607e666bc82 |
hex | b08402380bf |
12130063712447 has 4 divisors (see below), whose sum is σ = 12130085829840. Its totient is φ = 12130041595056.
The previous prime is 12130063712399. The next prime is 12130063712453. The reversal of 12130063712447 is 74421736003121.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12130063712447 - 218 = 12130063450303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12130063712647) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10214558 + ... + 11340075.
It is an arithmetic number, because the mean of its divisors is an integer number (3032521457460).
Almost surely, 212130063712447 is an apocalyptic number.
12130063712447 is a deficient number, since it is larger than the sum of its proper divisors (22117393).
12130063712447 is an equidigital number, since it uses as much as digits as its factorization.
12130063712447 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22117392.
The product of its (nonzero) digits is 169344, while the sum is 41.
Adding to 12130063712447 its reverse (74421736003121), we get a palindrome (86551799715568).
The spelling of 12130063712447 in words is "twelve trillion, one hundred thirty billion, sixty-three million, seven hundred twelve thousand, four hundred forty-seven".
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