Base | Representation |
---|---|
bin | 11011100101001010011000… |
… | …111000000111001100011111 |
3 | 120220111021011102112220001220 |
4 | 123211022120320013030133 |
5 | 111344344002443014444 |
6 | 1105552531403104423 |
7 | 34356465430116051 |
oct | 3345123070071437 |
9 | 526437142486056 |
10 | 121301031219999 |
11 | 357175298a3234 |
12 | 11730b51b12113 |
13 | 528b83b072657 |
14 | 21d50035718d1 |
15 | e054b8d77619 |
hex | 6e5298e0731f |
121301031219999 has 16 divisors (see below), whose sum is σ = 172145103759360. Its totient is φ = 75711966919040.
The previous prime is 121301031219997. The next prime is 121301031220027. The reversal of 121301031219999 is 999912130103121.
121301031219999 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 121301031219999 - 21 = 121301031219997 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121301031219997) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6226303329 + ... + 6226322810.
It is an arithmetic number, because the mean of its divisors is an integer number (10759068984960).
Almost surely, 2121301031219999 is an apocalyptic number.
121301031219999 is a deficient number, since it is larger than the sum of its proper divisors (50844072539361).
121301031219999 is a wasteful number, since it uses less digits than its factorization.
121301031219999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12452626350.
The product of its (nonzero) digits is 236196, while the sum is 51.
The spelling of 121301031219999 in words is "one hundred twenty-one trillion, three hundred one billion, thirty-one million, two hundred nineteen thousand, nine hundred ninety-nine".
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