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12130110313 = 37199326087
BaseRepresentation
bin10110100110000001…
…01100101101101001
31011022100221110010221
423103000230231221
5144320302012223
65323354210041
7606411144046
oct132300545551
934270843127
1012130110313
115165149462
122426423921
1311b40bb589
1483100a1cd
154aedc1b5d
hex2d302cb69

12130110313 has 4 divisors (see below), whose sum is σ = 12130473600. Its totient is φ = 12129747028.

The previous prime is 12130110301. The next prime is 12130110337. The reversal of 12130110313 is 31301103121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31301103121 = 231360917527.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12130110313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12130110353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125845 + ... + 200242.

It is an arithmetic number, because the mean of its divisors is an integer number (3032618400).

Almost surely, 212130110313 is an apocalyptic number.

It is an amenable number.

12130110313 is a deficient number, since it is larger than the sum of its proper divisors (363287).

12130110313 is an equidigital number, since it uses as much as digits as its factorization.

12130110313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 363286.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 12130110313 its reverse (31301103121), we get a palindrome (43431213434).

The spelling of 12130110313 in words is "twelve billion, one hundred thirty million, one hundred ten thousand, three hundred thirteen".

Divisors: 1 37199 326087 12130110313