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121301113310093 is a prime number
BaseRepresentation
bin11011100101001010011101…
…110001010000101110001101
3120220111021101011000111111202
4123211022131301100232031
5111344344140001410333
61105552543454355245
734356500444635553
oct3345123561205615
9526437334014452
10121301113310093
1135717571171792
1211730b754bbb25
13528b852085182
1421d501041dbd3
15e054c11905e8
hex6e529dc50b8d

121301113310093 has 2 divisors, whose sum is σ = 121301113310094. Its totient is φ = 121301113310092.

The previous prime is 121301113310063. The next prime is 121301113310099. The reversal of 121301113310093 is 390013311103121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121230185369764 + 70927940329 = 11010458^2 + 266323^2 .

It is an emirp because it is prime and its reverse (390013311103121) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 121301113310093 - 230 = 121300039568269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (121301113310099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60650556655046 + 60650556655047.

It is an arithmetic number, because the mean of its divisors is an integer number (60650556655047).

Almost surely, 2121301113310093 is an apocalyptic number.

It is an amenable number.

121301113310093 is a deficient number, since it is larger than the sum of its proper divisors (1).

121301113310093 is an equidigital number, since it uses as much as digits as its factorization.

121301113310093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1458, while the sum is 29.

The spelling of 121301113310093 in words is "one hundred twenty-one trillion, three hundred one billion, one hundred thirteen million, three hundred ten thousand, ninety-three".