Base | Representation |
---|---|
bin | 10001101001101101001… |
… | …010110000000000100110 |
3 | 11021221222220200001110201 |
4 | 101221231022300000212 |
5 | 124333222122441402 |
6 | 2325130011341114 |
7 | 153431401350013 |
oct | 21515512600046 |
9 | 4257886601421 |
10 | 1213012312102 |
11 | 428487910838 |
12 | 17710b45179a |
13 | 8a5043aa776 |
14 | 429d277a70a |
15 | 21847270687 |
hex | 11a6d2b0026 |
1213012312102 has 4 divisors (see below), whose sum is σ = 1819518468156. Its totient is φ = 606506156050.
The previous prime is 1213012312081. The next prime is 1213012312117. The reversal of 1213012312102 is 2012132103121.
It is a semiprime because it is the product of two primes.
It is a super-2 number, since 2×12130123121022 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1213012312102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 303253078024 + ... + 303253078027.
It is an arithmetic number, because the mean of its divisors is an integer number (454879617039).
Almost surely, 21213012312102 is an apocalyptic number.
1213012312102 is a deficient number, since it is larger than the sum of its proper divisors (606506156054).
1213012312102 is an equidigital number, since it uses as much as digits as its factorization.
1213012312102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 606506156053.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1213012312102 its reverse (2012132103121), we get a palindrome (3225144415223).
The spelling of 1213012312102 in words is "one trillion, two hundred thirteen billion, twelve million, three hundred twelve thousand, one hundred two".
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